0.006x^2+22=39

Solution for 0.006x^2+22=39 equation:

0.006x^2+22=39

We move all terms to the left:

0.006x^2+22-(39)=0

We add all the numbers together, and all the variables

0.006x^2-17=0

a = 0.006; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·0.006·(-17)
Δ = 0.408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.408}}{2*0.006}=\frac{0-\sqrt{0.408}}{0.012}
=-\frac{\sqrt{}}{0.012}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.408}}{2*0.006}=\frac{0+\sqrt{0.408}}{0.012}
=\frac{\sqrt{}}{0.012}
$